It takes a force of 22 N to push a 10 kg box horizontally with a constant velocity over concrete. What is the coefficient of kinetic friction between the box and the concrete?
My guess is 10 kg/22 N = 0.4545 but I'm not sure if you have to take in account vertical forces or if 0.4545 represents the static frictional force.
Well, well, well, looks like we have ourselves a friction-fueled puzzler here! Let's see if we can unwrap this conundrum with a dash of humor, shall we?
First of all, your guesswork is kind of heading in the right direction, but let's break it down bit by bit.
The force of 22 N is the amount of force needed to counteract the kinetic friction. Now, since the box is moving with a constant velocity, that means the force you're applying must be equal to the force of kinetic friction. So, we have two forces at play: your pushing force and the frictional force.
Now, to find the coefficient of kinetic friction, we need to use the equation:
force of kinetic friction = coefficient of friction * normal force
In this case, since the box is resting on the concrete surface, the normal force is equal to the weight of the box, which is given by:
normal force = mass * gravity
Plugging in the numbers, we get:
normal force = 10 kg * 9.8 m/s^2 = 98 N
So, the force of kinetic friction is equal to the pushing force of 22 N. Now let's rearrange the equation to find the coefficient of kinetic friction:
coefficient of kinetic friction = force of kinetic friction / normal force
coefficient of kinetic friction = 22 N / 98 N
And after a little math magic, we get:
coefficient of kinetic friction ≈ 0.2245
So, there you have it! The coefficient of kinetic friction between the box and the concrete is approximately 0.2245.
Remember, my friend, humor makes everything a little bit more enjoyable, even friction coefficients!
To find the coefficient of kinetic friction between the box and the concrete, you can use the equation:
Force of friction = coefficient of kinetic friction * normal force
Since the box is being pushed horizontally with a constant velocity, the vertical forces (such as weight and normal force) do not affect the calculation.
However, in this case, the force of friction is given by the pushing force of 22 N. Therefore, the equation becomes:
22 N = coefficient of kinetic friction * normal force
We need to find the normal force, which is equal to the weight of the box. The weight is given by:
Weight = mass * acceleration due to gravity
Weight = 10 kg * 9.8 m/s^2
Weight = 98 N
Now we can substitute the normal force into the equation:
22 N = coefficient of kinetic friction * 98 N
Rearranging the equation, we get:
coefficient of kinetic friction = 22 N / 98 N
coefficient of kinetic friction = 0.2245
Therefore, the coefficient of kinetic friction between the box and the concrete is approximately 0.2245.
To find the coefficient of kinetic friction between the box and the concrete, we need to consider the forces acting on the box.
When the box is moving with a constant velocity, it means that the applied force is equal to the force of kinetic friction.
The applied force is 22 N, so the force of kinetic friction is also 22 N.
Now, let's break down the forces acting on the box:
1. Weight: The weight of the box can be calculated by multiplying the mass (10 kg) by the acceleration due to gravity (9.8 m/s²). So, the weight is 10 kg * 9.8 m/s² = 98 N. The weight acts vertically downward.
2. Normal force: The normal force is the force exerted by the surface on the box perpendicular to the surface. When the box is on a flat surface, the normal force is equal to the weight of the box (98 N) because there is no vertical acceleration. The normal force acts vertically upward.
3. Force of kinetic friction: The force of kinetic friction is the force that opposes the motion of the box. It acts horizontally and is equal to the applied force (22 N) in this case.
Since the box is moving horizontally with a constant velocity, the applied force (22 N) is equal in magnitude but opposite in direction to the force of kinetic friction (22 N). Therefore, the coefficient of kinetic friction can be calculated as follows:
Coefficient of kinetic friction = Force of kinetic friction / Normal force
Coefficient of kinetic friction = 22 N / 98 N = 0.2245
So, the coefficient of kinetic friction between the box and the concrete is 0.2245.
Your initial guess of 0.4545 does not represent the coefficient of kinetic friction because it does not take into account the normal force or the fact that the box is moving with a constant velocity.
It's not static
yes, gravity counts
22 / (10 * g)