plse help me
24 (-3,-4) (3,-2)
27 (3,-8) (-2,5)
30. 0.2,1.1) (7,3)
a line passes throught the given point. write an equation for the liine in point slope form. then rewrite the euqation in slope intercept for plse help me with these three
I will do the second one, you do the rest, ok?
2) slope of line = (5+8)/-2-3) = -13/5
using the point (-2,5)
y-5 = (-13/5)(x+2)
Is this is what you mean by point-slope form?
I would now multiply by 5
5y - 25 = -13x - 26
13x + 5y + 1 = 0 , this is what we used to call general form
solve for y to get y = -(13/5)x - 1/5
this is the slope-yintercept form
thx a million for some reason i just don't get it but know i do thx you very much
hi amy its alan thx for the site
Sure, I can help you with that! To write an equation in point-slope form, we need to use the given point and the slope of the line.
Let's start with the first question:
1. 24 (-3,-4) (3,-2)
To find the slope of the line passing through the points (-3,-4) and (3,-2), we use the slope formula: m = (y2 - y1) / (x2 - x1).
The coordinates of the first point are (-3,-4) = (x1,y1), and the coordinates of the second point are (3,-2) = (x2,y2).
Plugging the values into the slope formula:
m = (-2 - (-4)) / (3 - (-3))
= (-2 + 4) / (3 + 3)
= 2 / 6
= 1/3
Now that we have the slope, we can use the point-slope form equation: y - y1 = m(x - x1).
Plugging in the values, we get:
y - (-4) = (1/3)(x - (-3))
y + 4 = (1/3)(x + 3)
This is the equation in point-slope form.
To rewrite it in slope-intercept form (y = mx + b), we need to isolate y:
y + 4 = (1/3)(x + 3)
y = (1/3)x + 1 - 4
y = (1/3)x - 3
So, the equation in slope-intercept form is y = (1/3)x - 3.
Follow the same process for the next two questions:
2. 27 (3,-8) (-2,5)
3. 30 (0.2,1.1) (7,3)
Calculate the slope using the formula, substitute the values in the point-slope form equation, and then convert it to slope-intercept form.