Another problem I need help with.

An auto race is held on a circular track. A car completes one lap in a time of 20.1 s, with an average tangential speed of 43.1 m/s. Find the following.

The following did not follow.

I apologize for that. Here is the entire question.

An auto race is held on a circular track. A car completes one lap in a time of 20.1 s, with an average tangential speed of 43.1 m/s. Find the following.

(a) the average angular speed in rad/s

(b) the radius of the track in m

a) Divide 2 pi radians (one lap) by 20.1 seconds. The answer will be in radians per second.
b) 43.1 m/s = (circumference)/20.1 s
= 2 pi R /(20.1 s)
R = (43.1 m/s)*20.1 s/(2 pi)= ? m

To find the average angular speed in rad/s (part a), we need to divide the angle covered by the car in one lap (which is 2π radians) by the time taken for one lap (which is 20.1 seconds).

So, the average angular speed in rad/s = 2π radians / 20.1 s.

To find the radius of the track (part b), we can use the average tangential speed of the car (43.1 m/s) and the time taken for one lap (20.1 seconds).

We know that the tangential speed is equal to the circumference of the track divided by the time taken. So, we can set up the equation:

43.1 m/s = (circumference) / 20.1 s

We also know that the circumference of a circular track is equal to 2π times the radius (C = 2πR).

So, we can rewrite the equation as:

43.1 m/s = (2πR) / 20.1 s

Now, solve for R by multiplying both sides of the equation by 20.1 s and dividing by 2π:

R = (43.1 m/s) * 20.1 s / (2π)

Calculating this expression will give you the radius of the track in meters.