the solubility of aspartic acid in water is .500 g in 100 mL at 25 degrees C. If .251 g of aspartic acid is dissolved in 50. mL of water at 50 degrees C and let solution cool to 25 degrees C. is the solution supersaturated, saturated, or unsaturated. the solution was not stirred, shaked, or disturbed.
To determine if the solution is supersaturated, saturated, or unsaturated, we need to compare the amount of aspartic acid dissolved in the solution at 25 degrees C to its solubility at that temperature. Here's how you can calculate it:
Step 1: Convert the given weight of aspartic acid to grams.
Given: 0.251 g of aspartic acid
Step 2: Calculate the solubility of aspartic acid in the given volume of water at 50 degrees C.
Given:
- Dissolved Mass: 0.251 g
- Volume: 50. mL
Use the formula: Solubility (g/mL) = Mass of solute (g) / Volume of solvent (mL)
Solubility = 0.251 g / 50. mL
Step 3: Since the solution is allowed to cool to 25 degrees C, we need to calculate the maximum amount of aspartic acid that can be dissolved at this temperature.
Given:
- Solubility at 25 degrees C: 0.500 g / 100 mL
- Volume: 50. mL
Use the formula: Mass of solute = Solubility (g/mL) * Volume of solvent (mL)
Max solubility = 0.500 g / 100 mL * 50. mL
Now, compare the dissolved mass of aspartic acid (0.251 g) with the maximum solubility at 25 degrees C.
If the dissolved mass is less than the maximum solubility, the solution is unsaturated. If the dissolved mass is equal to the maximum solubility, the solution is saturated. If the dissolved mass is greater than the maximum solubility, the solution is supersaturated.
Plug in the values calculated in Step 2 and Step 3 to make the comparison and determine whether the solution is supersaturated, saturated, or unsaturated.