I need some help with my Algebra project. I already finished task on
but I'm unsure of how to solve my inequality. Please help.
Task 1
Summary: You are going to decide on a summer business to start. Figure out what you will do, how much it will cost you, and how much you will charge. It will be helpful to research something you can make sell, that is reasonable.
Total amount of money you will be investing:
$100
Describe the setup of your business:
Cost to make each item: $0.20 per cup and $2.33 per gallon
Selling price of each item: $1.00 per cup
Task 2
Summary: In Task 1 you determined how much money you will be spending to start your business. You may not exceed this limit when making your product.
Write an inequality to represent the limit you may not exceed when spending to make your product
X <= 100
Solve this inequality:
Did your teacher grade your project yet?if so can you help me?
did you get task 3?
I have task 3
$0.20x + $2.30y - $1.00z < $100
To solve the inequality "X <= 100," you need to isolate the variable X. Here's how you can do it:
1. Subtract 100 from both sides of the inequality to move the constant to the other side: X - 100 <= 0.
2. The resulting inequality now states that X minus 100 is less than or equal to 0.
To determine the value of X that satisfies this inequality, we'll set up a number line and identify the interval where X falls.
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0 100 | |
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Now, since the inequality includes "less than or equal to," we need to include the endpoint, 100, in the solution. This means that any value of X that is less than or equal to 100 will satisfy the inequality.
Therefore, the solution to the inequality X <= 100 is X = (-∞, 100] (read as "X is any value less than or equal to 100"). In the context of the task, this means that the cost you spend to make your product (X) must be less than or equal to $100.