HOW TO PREPARE 1 M GUAICOL FROM LIQUID GUAICOL SOLUTION MOLECULAR WEIGHT 124.14
DENSITY 1.11
To prepare 1 mg of guaiacol, we need to calculate the volume of the liquid guaiacol solution required, considering its molecular weight and density.
First, let's convert the mass of guaiacol from milligrams to grams since the molecular weight is typically expressed in grams. 1 mg is equal to 0.001 grams.
Next, we can use the formula:
Volume (V) = Mass (m) / Density (D)
Where:
- Volume (V) is the volume of the guaiacol solution needed in liters (L)
- Mass (m) is the mass of guaiacol in grams (g)
- Density (D) is the density of the guaiacol solution in grams per milliliter (g/mL).
We know that the density of the guaiacol solution is 1.11 g/mL.
Let's do the calculation:
m = 0.001 g
D = 1.11 g/mL
V = 0.001 g / 1.11 g/mL
To calculate the volume, we divide the mass by the density.
Now, let's convert the volume to milliliters, as it is a more practical unit for measuring small volumes. There are 1000 mL in 1 L.
V (in mL) = V (in L) x 1000
V (in mL) = (0.001 g / 1.11 g/mL) x 1000
Let's calculate the result:
V (in mL) = (0.001 / 1.11) x 1000
V (in mL) = 0.900 mL
Therefore, to prepare 1 mg of guaiacol, you would need approximately 0.900 mL of the liquid guaiacol solution with a molecular weight of 124.14 and a density of 1.11 g/mL.