A varies jointly as R1 and R2 and inversely as the sqaure of L. Find A when R1=180, R2=8,L=5, and k=3/2

P.S the 1 and 2 next to the R are exponents at the bottom of R and not at the top.

A = k*R1*R2/L^2

"exponents" at the bottom are called subscripts.

To find the value of A when R1 = 180, R2 = 8, L = 5, and k = 3/2, we can use the formula for variation. The variation states that A varies jointly as R1 and R2, and inversely as the square of L. Mathematically, this can be expressed as:

A = k * R1^a * R2^b / L^c

where k is a constant, a, b, and c are exponents, and ^ denotes exponentiation.

Substituting the given values into the formula, we have:

A = (3/2) * 180^a * 8^b / 5^c

To find the values of a, b, and c, we need additional information or equations that relate A, R1, R2, and L.

Please provide additional information or equations to determine a, b, and c, and the constant k.