A box open at the top has its outer dimensions 10cm,9cm & 2.5cm and its thickness 0.5mm. Find the volume of the metal
(10+.1)(9+.1)(2.5+.1) - 10*9*2.5 = 13.966 cm^3
To find the volume of the metal, we first need to determine the dimensions of the inner box.
Given that the outer dimensions of the box are 10cm, 9cm, and 2.5cm, and the thickness of the metal is 0.5mm, we can calculate the inner dimensions as follows:
Inner Length = Outer Length - 2 x Thickness
Inner Width = Outer Width - 2 x Thickness
Inner Height = Outer Height - Thickness
Plugging in the values:
Inner Length = 10cm - 2 x 0.5mm = 10cm - 1mm = 9.9cm
Inner Width = 9cm - 2 x 0.5mm = 9cm - 1mm = 8.9cm
Inner Height = 2.5cm - 0.5mm = 2.5cm - 0.1cm = 2.4cm
Now that we have the dimensions of the inner box, we can find the volume of the metal. The volume of a rectangular solid (box) is calculated by multiplying its length, width, and height.
Volume of the metal = Inner Length x Inner Width x Inner Height
= 9.9cm x 8.9cm x 2.4cm
= 209.592 cm³
Therefore, the volume of the metal is 209.592 cm³.