h2po4(aq) + co34(aq) hco3 (aq) + hpo42 (aq)
Adam, I can't begin to decipher your post. No caps, no arrow, no differentiation between reactants and products, no question.
The chemical equation you provided seems incomplete. It is missing information about the state symbols and coefficients. Nonetheless, I can explain how to balance a chemical equation if that's what you're asking for.
To balance a chemical equation, you need to ensure that the number of atoms of each element is equal on both sides of the equation.
Let's assume the following balanced equation:
H2PO4- (aq) + CO32- (aq) → HCO3- (aq) + HPO42- (aq)
To balance this equation, we start by counting the number of atoms on each side:
On the left side (reactants):
- Hydrogen (H): 2
- Phosphorus (P): 1
- Oxygen (O): 5
On the right side (products):
- Hydrogen (H): 2
- Carbon (C): 1
- Phosphorus (P): 1
- Oxygen (O): 7
To balance the equation, we need to adjust the coefficients:
H2PO4- (aq) + CO32- (aq) → HCO3- (aq) + HPO42- (aq)
1 1 1 1
The coefficients indicate the number of molecules or ions involved in the reaction. By adjusting the coefficients, we can balance the equation. In this case, the balanced equation becomes:
H2PO4- (aq) + CO32- (aq) → 2 HCO3- (aq) + HPO42- (aq)
Now, both sides of the equation have balanced numbers of atoms:
On the left side (reactants):
- Hydrogen (H): 2
- Carbon (C): 1
- Phosphorus (P): 1
- Oxygen (O): 5
On the right side (products):
- Hydrogen (H): 2
- Carbon (C): 2
- Phosphorus (P): 1
- Oxygen (O): 7
Hope this helps! Let me know if you have any further questions.