A coin is tossed and a three-sector spinner is spun. What are the chances of getting 1 Heads and a 2?
*Please answer with a simplified fraction*
If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.
1/2 * 1/3 = ?
To find the probability of getting 1 Heads and a 2 in this scenario, we need to consider the probabilities of both events happening individually and then multiply them together.
First, let's find the probability of getting 1 Heads from the coin toss. There are two possible outcomes: Heads (H) or Tails (T). Since a coin has only 2 sides, the probability of getting Heads is 1/2.
Next, let's find the probability of getting a 2 from the spinner. As you mentioned, the spinner has three sectors. Since the desired outcome is getting a 2, and there is only one 2-sector out of the three, the probability of getting a 2 is 1/3.
To find the overall probability of both events happening together, we multiply the two probabilities together:
1/2 * 1/3 = 1/6
Therefore, the chances of getting 1 Heads and a 2 in this scenario is 1/6.