A bus contain 42 passengers the number of male is 5 times the number of female how many famale in the bus
f + 5f = 42
6f = 42
f = ?
a bus contain 42 passengers. the number of males is 5 times the number of females how many females are in the bus
Let's denote the number of females on the bus as 'F'. According to the problem, the number of males is 5 times the number of females. So, the number of males would be 5F.
The total number of passengers on the bus is given to be 42. Therefore, the sum of the number of females and males should be 42:
F + 5F = 42
Combining like terms:
6F = 42
Now, let's solve for F by dividing both sides of the equation by 6:
F = 42/6
Simplifying:
F = 7
Hence, there are 7 females on the bus.
To find the number of females on the bus, we need to set up a system of equations based on the given information.
Let's assume the number of female passengers is represented by 'f', and the number of male passengers is represented by 'm'.
From the given information, we know that the bus contains a total of 42 passengers: f + m = 42. (Equation 1)
We also know that the number of male passengers is 5 times the number of female passengers: m = 5f. (Equation 2)
To solve this system of equations, we can substitute the value of 'm' from Equation 2 into Equation 1:
f + 5f = 42.
Combining like terms, we get:
6f = 42.
Dividing both sides of the equation by 6, we find that:
f = 7.
Therefore, there are 7 females on the bus.