Determine whether the lines y=8x-5 and y=(-2÷16)x-3 are parallel or perpendicular or neither parallel nor perpendicular.

No

the slope of the 2nd is -2/16 = -1/8

which is the negative reciprocal of the slope of the first.
Thus, the lines are perpendicular.

To determine whether two lines are parallel, perpendicular, or neither parallel nor perpendicular, we need to compare their slopes.

The first line is in the form y = mx + b, where m is the slope. The slope of the first line is 8.

The second line is in the form y = mx + b, where m is the slope. However, the second line is given in a different format, so we need to simplify it first.

y = (-2 ÷ 16)x - 3 simplifies to y = (-1/8)x - 3. From this format, we can see that the slope of the second line is (-1/8).

Now, we compare the slopes of the two lines:

If the slopes of two lines are equal, then the lines are parallel.

If the slopes of two lines are negative reciprocals of each other (the product of the slopes is -1), then the lines are perpendicular.

If the slopes are neither equal nor negative reciprocals of each other, then the lines are neither parallel nor perpendicular.

In this case, the slope of the first line is 8, and the slope of the second line is (-1/8). The slopes are not equal, nor are they the negative reciprocals of each other. Therefore, the lines y=8x-5 and y=(-2÷16)x-3 are neither parallel nor perpendicular.