If thrice of "A's" age 6 years ago be subtracted from twice his present age the result would be equal to his present age. Find "A's" present age.

2A-3(A-6)=A

2A-3A+18=A
2A=18
divide both sides by 2
A=9 years old

Let the value be "x"

2x-3(x-6)=x
x=3x-18
2x=18
x=9
This the present age of A is 9 years
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9 years old

Helpful for me

To find "A's" present age, let's first assume "A's" present age to be x.

According to the given information, twice "A's" present age minus three times his age 6 years ago is equal to his present age.
Mathematically, this can be represented as: 2x - 3(x - 6) = x.

Simplifying the equation:
2x - 3x + 18 = x,
- x + 18 = x.

Combining like terms:
18 = 2x.

Divide both sides of the equation by 2:
18/2 = x,
9 = x.

Therefore, "A's" present age is 9 years.

2A - 3(A-6) = A

Solve for A.