Numbers subtract two times a number from half of its Square give a result of 16
Someone pls help this is due in 20mins
(1/2)x^2 - 2x = 6
times 2
x^2 - 4x = 12
x^2 - 4x - 12 = 0
it factors:
(x - 6)(x + 2) = 0
now follow the steps I showed you here
http://www.jiskha.com/display.cgi?id=1479598571
It's supposed to be 16 not 6 tho
To solve this problem, let's break it down step by step.
Let's call the number we're trying to find "x".
First, let's set up the equation based on the information given:
x - 2x = (1/2)x^2 - 16
Now, let's simplify the equation:
-x = (1/2)x^2 - 16
Next, let's get rid of the fraction by multiplying the entire equation by 2:
-2x = x^2 - 32
Now, let's move all the terms to one side of the equation to set it equal to zero:
x^2 + 2x - 32 = 0
Finally, let's factor or use the quadratic formula to solve for x.
Since -32 can be factored as (-4)(8) and the middle term is 2x, we can rewrite the equation as:
(x - 4)(x + 8) = 0
Setting each factor equal to zero, we have:
x - 4 = 0 or x + 8 = 0
Solving for x gives us:
x = 4 or x = -8
So the two possible values for the number are 4 or -8.