Solve each inequality
1. m-7<6=
2. n-8>5=
3. p+5<10=
4. there are 20 students and unknown number of adults, the bus can hold at least 35 people. What is the greatest number of adults who can chaperon?
1.D
2.A
3.B
4.C
100%
m < 13
n > 13
p < 5
I think you mean at most 35 people
20 + a <= 35
a <= 15
so no more than 15
Damon is a retired professor.
Mabey you should rehire him cause he just helped me out a lot.
Cat Is 100 percent right
thx for the help damon, and yea I meant at most 35 people. What grade are you in?
CAT IS CORRECT 100% DABC THANKS CAT TRUST CAT
if ur in connexus
thanks cat
To solve each inequality, we will isolate the variable on one side of the equation.
1. m - 7 < 6
To isolate m, add 7 to both sides of the equation:
m - 7 + 7 < 6 + 7
Simplify:
m < 13
2. n - 8 > 5
To isolate n, add 8 to both sides of the equation:
n - 8 + 8 > 5 + 8
Simplify:
n > 13
3. p + 5 < 10
To isolate p, subtract 5 from both sides of the equation:
p + 5 - 5 < 10 - 5
Simplify:
p < 5
Now, let's move on to the next question:
4. To find the greatest number of adults who can chaperon, we need to subtract the number of students from the capacity of the bus.
Given that there are 20 students and the bus can hold at least 35 people, we can set up the following inequality:
A + 20 ≤ 35
Where A represents the number of adults.
To isolate A, subtract 20 from both sides of the equation:
A + 20 - 20 ≤ 35 - 20
Simplify:
A ≤ 15
Therefore, the greatest number of adults who can chaperon is 15.