If dissolving 2g of ionic salt causes 50ml of water in increase temp. by 15 degrees Celsius at constant pressure, what would be the change in temperature if 6g of the same ionic salt were used instead? Assume the volume of solution remains the same.
dT = 15 x (6/2) = /
To find the change in temperature when 6g of the same ionic salt is dissolved instead of 2g, we can use the concept of heat capacity.
The heat capacity is a measure of how much heat energy is required to raise the temperature of a substance by one degree Celsius. In this case, we are assuming that the heat capacity of the water and the solution is constant.
Given that dissolving 2g of the ionic salt causes a temperature increase of 15 degrees Celsius, we can calculate the heat capacity of the solution using the formula:
Heat Capacity = (Mass of the solution) x (Change in temperature)
First, convert the volume of water from milliliters to grams assuming the density of water is 1g/ml:
Mass of water = 50ml x 1g/ml = 50g
Next, calculate the heat capacity of the solution using the mass of the water and the change in temperature:
Heat Capacity = (50g) x (15°C) = 750 calories
Now, we can use the heat capacity to find the change in temperature when 6g of the same ionic salt is dissolved:
Change in temperature = (Heat capacity) / (Mass of the solution)
Since the volume of the solution remains the same, the mass of the solution will be the sum of the mass of water and the mass of the ionic salt:
Mass of solution = Mass of water + Mass of salt
Mass of solution = 50g + 6g = 56g
Therefore, the change in temperature when 6g of the ionic salt is dissolved will be:
Change in temperature = 750 calories / 56g = 13.39 degrees Celsius
So, the change in temperature would be approximately 13.39 degrees Celsius.