A rectangle has width the same as side of a square whose perimeter is 20m. the length of the rectangle is 9m. Find the perimeter of this rectangle.
W=L+20m
2L+2W=9
2L+2(w+20m)=9
2L+2w+20=9
4l+20=9
4L=20+9
4L=29
L=29/4
answered below. This is the third post of this problem.
To find the perimeter of a rectangle, you need to add up the lengths of all four sides. In this case, the length of the rectangle is given as 9m.
To find the width of the rectangle, you are given that the width is the same as the side of a square whose perimeter is 20m. Since the perimeter of a square is the sum of all four sides, you can divide the given perimeter of 20m by 4 to find the length of each side.
20m/4 = 5m
So, the width of the rectangle is 5m.
Now that you know the length and width of the rectangle, you can calculate its perimeter using the formula:
Perimeter = 2 * (Length + Width)
Plugging in the values:
Perimeter = 2 * (9m + 5m)
Perimeter = 2 * 14m
Perimeter = 28m
Therefore, the perimeter of the rectangle is 28m.