The perimeter of the floor of a room is 18m and its height is 3m. What is the area of 4 walls of the room?
3*18 = 54 m^2
54 m^2 is the right answer ..
108
To find the area of the four walls of the room, we first need to determine the dimensions of the walls.
Considering the perimeter of the floor, we know that the sum of all sides of the floor is 18m. Since the floor is rectangular, we can assume that two opposite sides have the same length and the other two opposite sides have the same length. Let's denote the width of the room as "w" and the length as "l".
Considering the height of the room, we can determine that the walls will have the same height, which is 3m.
Now, let's calculate the dimensions of the walls:
Perimeter of the floor = 2 * (length + width) = 18m
Therefore, (length + width) = 9m
Since we only have two variables, we cannot solve the equation exactly. However, we can solve for either length or width in terms of the other variable.
Let's assume we solve for length in terms of width:
length = 9m - width
Now, we can use the area formula to calculate the area of the four walls.
Area of the four walls = 2(2*length*height + 2*width*height)
Substituting the values, we get:
Area of the four walls = 2(2*(9m-width)*3m + 2*width*3m)
Simplifying further:
Area of the four walls = 2(54m - 6*width + 6*width)
Area of the four walls = 2(54m)
Area of the four walls = 108m²
Therefore, the area of the four walls of the room is 108 square meters.