How many moles of water vapor react to yield 546.234 moles of hydrogen?
React with what to form what? I assume that is to decompose to H2 and O2 but I don't know that.
Write the equation.
2H2O ==> 2H2 + O2
546.234 mols H2 x (2 mol H2O/2 mol H2) = 546.234 x (2/2) = 546.234 x 1/1 = 546.234 mol H2O.
It's done with the coefficients.
2H2O
To determine the number of moles of water vapor that react to yield 546.234 moles of hydrogen, we need to determine the molar ratio between water and hydrogen in the reaction.
The balanced equation for the reaction is:
2H₂O(l) → 2H₂(g) + O₂(g)
From the balanced equation, we can see that 2 moles of water reacts to yield 2 moles of hydrogen.
So, the molar ratio is 2 moles of water to 2 moles of hydrogen.
Now, we can set up a proportion to solve for x (number of moles of water vapor):
2 moles of water / 2 moles of hydrogen = x moles of water vapor / 546.234 moles of hydrogen
Simplifying the proportion:
2/2 = x/546.234
1 = x/546.234
Multiplying both sides by 546.234:
x = 546.234
Therefore, 546.234 moles of water vapor reacts to yield 546.234 moles of hydrogen.
To determine the number of moles of water vapor that react to yield 546.234 moles of hydrogen, we need to use the balanced chemical equation for the reaction. Let's assume the reaction is:
2H2O (water vapor) → 2H2 (hydrogen) + O2 (oxygen)
From the balanced equation, we can see that 2 moles of water vapor react to produce 2 moles of hydrogen. Therefore, we can set up a ratio:
2 moles of water vapor : 2 moles of hydrogen
Using this ratio, we can find the number of moles of water vapor that react by setting up a proportion:
2 moles of water vapor / 2 moles of hydrogen = x moles of water vapor / 546.234 moles of hydrogen
Solving for x, the number of moles of water vapor, we get:
x = (2 moles of water vapor / 2 moles of hydrogen) * 546.234 moles of hydrogen
x = 273.117 moles of water vapor
Therefore, 273.117 moles of water vapor will react to yield 546.234 moles of hydrogen.