could someone check my work.
The width of a rectagular is one -half the length. the perimeter of the rectangler is 72 inches Find the length of the picture
2L+2w=72
2L(1/2)+2w=72
2L(5)+2w=72
10L+2w=72
12=72
L=12/72
L=6
answered below
To check your work, let's substitute the value of the length (L=6) back into the original equation and see if it satisfies the given conditions.
The width of the rectangle is one-half the length, so the width (w) is equal to (1/2)L.
The perimeter of a rectangle is given by the formula P = 2L + 2w.
Substituting L=6 and w=(1/2)L into the formula:
P = 2(6) + 2(1/2)(6) = 12 + 6 = 18
Since the perimeter is given as 72 inches, and we got 18 inches as the result, it means there is an error in your calculation.
Let's review the correct steps to solve the problem:
1. Start with the equation: 2L + 2w = 72
2. Substitute w = (1/2)L into the equation: 2L + 2(1/2)L = 72
3. Simplify: 2L + L = 72
4. Combine like terms: 3L = 72
5. Divide both sides by 3: L = 72/3
6. Calculate the value of L: L = 24
Therefore, the correct length of the rectangle is 24 inches.