In which solutions will a white precipitate be observed when aqueous copper (ii) chloride is added to it?
A) Sodium hydroxide
B) Potassium carbonate
C) Lead (ii) nitrate
D) Magnesium Sulfate
Could someone tell me the ans and explain it to me, thk u!
This is hardly organic chemistry.
Some reasons for pptn rxns.
1. A ppt is formed.
2. A gas is formed.
3. A weak electrolyte is formed.
You asked only about pptn so look at the equations and see if a ppt will form. Basically this requires that you know the solubility rules for compounds. Lastly, you need to know the colors of a ppt formed.
A. Adding NaOH gives Cu(OH)2.
B. Adding K2CO3 gives CuCO3.
C. Adding Pb(NO)2 gives PbCl2.
D. no ppt formed.
Most Cu compounds are blue, green, or blue/green in color. PgCl2 is white.
To determine in which solutions a white precipitate will be observed when aqueous copper (II) chloride is added, we need to consider the solubility rules or general solubility guidelines.
The solubility rules state that most chloride salts are soluble, except those of silver, lead (II), and mercury (I). Additionally, copper (II) chloride is soluble in water.
Now, let's analyze each option:
A) Sodium hydroxide:
When aqueous copper (II) chloride is added to sodium hydroxide, a reaction occurs to form copper (II) hydroxide, which is a pale blue precipitate. Therefore, a white precipitate won't be observed in this solution.
B) Potassium carbonate:
When aqueous copper (II) chloride is added to potassium carbonate, a reaction takes place to produce copper (II) carbonate, which is a greenish-blue precipitate. Once again, a white precipitate won't be formed.
C) Lead (II) nitrate:
When aqueous copper (II) chloride is added to lead (II) nitrate, a double displacement reaction occurs, resulting in the formation of lead (II) chloride and copper (II) nitrate. Since lead (II) chloride is insoluble, a white precipitate will be observed in this solution.
D) Magnesium sulfate:
When aqueous copper (II) chloride is added to magnesium sulfate, no reaction occurs since both copper (II) chloride and magnesium sulfate are soluble in water. Hence, a white precipitate won't be formed.
Therefore, the correct answer is C) Lead (II) nitrate.
Remember, in such scenarios, it is helpful to understand the solubility rules or consult a solubility table to determine the possible formation of a precipitate.