Identify the element that has a ground state electronic configuration of [Ar]4s23d104p 4

To identify the element with a ground state electronic configuration of [Ar]4s23d104p4, we need to understand the electron configuration notation.

In the electron configuration notation, the first part represents the noble gas configuration, which is the electronic configuration of the nearest noble gas element. In this case, [Ar] represents the electronic configuration of argon (Ar).

The second part represents the additional electrons beyond the noble gas configuration. In this case, 4s23d104p4 represents the additional electrons.

By looking at the given electronic configuration, we can see that there are 2 electrons in the 4s orbital (4s2), 10 electrons in the 3d orbital (3d10), and 4 electrons in the 4p orbital (4p4).

Adding up all the electrons, we get a total of 2 + 10 + 4 = 16 electrons.

The element with 16 electrons and the given electronic configuration [Ar]4s23d104p4 is sulfur (S). Sulfur has an atomic number of 16, which corresponds to the number of electrons. Therefore, the element with the given configuration is sulfur.

The element with a ground state electronic configuration of [Ar]4s23d104p4 is Selenium (Se).

Just add the electrons, protons will be the same, look up the atomic number.18+2+10+4 looks like 34 = Se to me.