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A MAN is now 3 times as old as his son. In 10 years time, the sum of their ages will be 76. How old the son.

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  1. M=3S
    M+10+S+10=76

    3S+10+S+10=76
    4S=56
    S=14
    M=3*14

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    bobpursley
  2. (x+10) + (3x+10) = 76

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  3. M = 3S

    (M+10) + (S+10) = 76

    Substitute 3S for M in the second equation and solve for S. Insert that value into the first equation to solve for M. Check by putting both values into the second equation.

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