A MAN is now 3 times as old as his son. In 10 years time, the sum of their ages will be 76. How old the son.
M=3S
M+10+S+10=76
3S+10+S+10=76
4S=56
S=14
M=3*14
(x+10) + (3x+10) = 76
M = 3S
(M+10) + (S+10) = 76
Substitute 3S for M in the second equation and solve for S. Insert that value into the first equation to solve for M. Check by putting both values into the second equation.
To find the age of the son, we can create two equations based on the given information.
Let's assume the current age of the son is S.
According to the problem, the current age of the man is 3 times the age of his son. So, the current age of the man would be 3S.
In 10 years, the age of the son will be S + 10, and the age of the man will be 3S + 10.
The problem also states that in 10 years, the sum of their ages will be 76. So, we can write the equation:
(S + 10) + (3S + 10) = 76
Simplifying this equation:
4S + 20 = 76
Subtracting 20 from both sides:
4S = 56
Dividing both sides by 4:
S = 14
Therefore, the son is currently 14 years old.