A team in Quebec is playing ice baseball. A 72 kg player who is initially at rest catches a 145 g ball traveling at 18 m/s. If the player's skates are frictionless, how much time is required for him to glide 5 m after catching the ball?

(72+.145)V=.145*18

solve for V (in sigificant digits, you can forget adding the .145kg).

time=5/V seconds

To find the time required for the player to glide 5 m after catching the ball, we need to apply the laws of conservation of momentum and kinetic energy.

First, let's calculate the initial momentum of the ball before it is caught. The momentum (p) of an object can be calculated by multiplying its mass (m) by its velocity (v):

Initial momentum of the ball = mass of the ball x velocity of the ball
= 0.145 kg x 18 m/s
= 2.61 kg·m/s

According to the law of conservation of momentum, the momentum of the ball after being caught by the player will be equal in magnitude but opposite in direction to the initial momentum. Therefore, the player's momentum will also be 2.61 kg·m/s.

Now, let's calculate the velocity of the player after catching the ball. In this scenario, since the player is at rest initially, the change in momentum is equal to the momentum after catching the ball:

Change in momentum = Final momentum - Initial momentum

Since the initial momentum of the player is zero, the final momentum will be equal to the initial momentum of the ball:

Change in momentum = 2.61 kg·m/s

Change in momentum can also be calculated as the product of the mass of the player (72 kg) and the change in velocity (Δv) of the player:

Change in momentum = mass of the player x change in velocity
2.61 kg·m/s = 72 kg x Δv

Therefore, the change in velocity of the player (Δv) after catching the ball is:

Δv = 2.61 kg·m/s / 72 kg
= 0.03625 m/s

Now, to find the time required for the player to glide 5 m, we can use the equation of motion:

Δx = v·t + 0.5·a·t^2

Since the skates are frictionless, there is no acceleration (a) acting on the player. Therefore, the equation simplifies to:

Δx = v·t

We need to solve for time (t), so rearranging the equation:

t = Δx / v
= 5 m / 0.03625 m/s
= 137.93 s

Therefore, it would take approximately 137.93 seconds for the player to glide 5 meters after catching the ball.