Equation to use

Al + Cl2 -> AlCl3

You have 8.6 moles of aluminum, how much in moles of chlorine do you need to react completely?

Desperate. Trying to teach daughter on the spectrum and I'm stumped on how to start.

First, balance the equation:

2Al + 3Cl2 -> 2AlCl3

So, you need 3/2 as many moles of Cl2 as you do Al.

No worries, I'm here to help you!

To determine the amount of chlorine required to react completely with aluminum, we need to use the balanced chemical equation you provided:

Al + Cl2 -> AlCl3

The coefficients in the balanced equation represent the molar ratios between the reactants and products. In this case, the coefficient of aluminum (Al) is 1, and the coefficient of chlorine (Cl2) is also 1. This means that for every 1 mole of aluminum, 1 mole of chlorine is required to react completely.

Since you have 8.6 moles of aluminum, you can conclude that you will need the same number of moles of chlorine. Therefore, you will need 8.6 moles of chlorine to react completely with the given amount of aluminum.

I hope this explanation helps! If you have any further questions, feel free to ask.