For every 5 highlighters that Agnes buys , she gets 1 free. If Agnes needs 80 highlighters, what is the least number of highlighters she has to buy?

80/6 = 13.3

so say she buys 13 * 5 = 65
then she gets 65/5 = 13 free
which is 78

so she needs to buy 2 more
65 + 2 = 67

Gillian has three ropes measuring 54 cm, 108 cm and 189 cm. She cuts them into equal pieces. The length of each piece is the longest possible she can cut. What is the length of each piece of rope?

To find the least number of highlighters Agnes has to buy, we'll determine the total number of highlighters she will receive for free.

If Agnes receives 1 free highlighter for every 5 she buys, then for every 5 + 1 = 6 highlighters, she will receive 1 for free.

To calculate the number of sets of 6 highlighters in 80, we divide 80 by 6: 80 ÷ 6 = 13 remainder 2.

This means that Agnes can get 13 sets of 6 highlighters (which equals 78 highlighters), and she will have 2 leftover highlighters.

Therefore, the least number of highlighters Agnes has to buy is 78+2 = 80.

To find the least number of highlighters that Agnes has to buy, we need to consider the fact that for every 5 highlighters she buys, she gets 1 free. This means that for each set of 5 highlighters, Agnes is effectively receiving 6 highlighters (5 purchased, 1 free).

To calculate the least number of highlighters Agnes needs to buy, we can use division. Divide the desired number of highlighters (80) by the number of highlighters in each set (6):

80 ÷ 6 = 13.33 (rounded to the nearest whole number)

Since Agnes cannot purchase a fraction of a highlighter, she would need to buy the whole number of sets required. In this case, she would need to buy 13 sets of 5 highlighters, which would give her 13 multiplied by 6 highlighters (including the free ones).

13 sets x 6 highlighters per set = 78 highlighters

Therefore, the least number of highlighters Agnes has to buy is 78.