find the 8th term in the expension of [(x)^1/2 +2/(x)^1/2]^12
The 8th term of (a+b)^12 is, according to the binomial theorem, 12C7 a^(12-7)b^7
12C7 √x^5*(2/√x)^7 = 792 * x^(5/2) * 128/x^(7/2) = 101376/x
12C7 √x^5*(2/√x)^7 = 792 * x^(5/2) * 128/x^(7/2) = 101376/x