what volume of a 0.20M potassium sulfate solution contains 57g potassium sulfate?
mols = grams/molar mass. You know molar mass and grams, solve for mols.
Then M = mols/L. You know mols and M, solve for L.
To find the volume of a solution, we can use the formula:
(grams of solute) / (molarity × molar mass of solute) = volume
First, let's calculate the molar mass of potassium sulfate (K2SO4):
Atomic mass of potassium (K) = 39.10 g/mol
Atomic mass of sulfur (S) = 32.06 g/mol
Atomic mass of oxygen (O) = 16.00 g/mol
Molar mass of K2SO4 = (2 × 39.10 g/mol) + 32.06 g/mol + (4 × 16.00 g/mol) = 174.25 g/mol
Now, we can calculate the volume of the solution:
Volume = (57g) / (0.20M × 174.25g/mol) ≈ 0.82 L (rounded to two decimal places)
Therefore, approximately 0.82 liters of the 0.20M potassium sulfate solution would contain 57g of potassium sulfate.