How would I find the moles of NaOH solution that was used to titrate?
I have 20.01mL of HCl used and 15.95mL of NaOH solution was used to titrate.
mols = M x L = ?
To find the moles of NaOH solution used to titrate, you will need to use stoichiometry and the known volume and concentration of the HCl solution used.
First, let's calculate the moles of HCl used. To do this, you can use the following formula:
moles of HCl = concentration of HCl (in mol/L) × volume of HCl used (in L)
However, we need to convert the volume of HCl used from milliliters (mL) to liters (L). Since 1 L is equal to 1000 mL, the volume of HCl used is 20.01 mL ÷ 1000 mL/L = 0.02001 L.
Next, let's assume that the concentration of HCl is provided. For this example, let's say the concentration of HCl is 0.1 mol/L.
Using the given information, we can calculate the moles of HCl used:
moles of HCl = 0.1 mol/L × 0.02001 L = 0.002001 mol
Now, since the reaction between HCl and NaOH is a 1:1 ratio according to the balanced chemical equation:
HCl + NaOH → NaCl + H2O
This means that for every mole of HCl, one mole of NaOH is consumed.
Therefore, the number of moles of NaOH used would be the same as the moles of HCl used. In this case, the moles of NaOH solution used to titrate would be 0.002001 mol.
Please note that the final answer assumes that the concentration of the NaOH solution is the same as the concentration of HCl. If the concentration of NaOH is different, you will need to adjust the calculations accordingly.