what would the concentration of the solution of a sulfuric acid be titration of a 25.0 ml sample of acid required 20.00 ml of a 0.20 naoh standardized solution for it to become neutralized
2NaOH + H2SO4 ==> Na2SO4 + 2H2O
mols NaOH = M x L = ?
Look at the coefficients in the balanced equation. 1 mol H2SO4 = 2 mols NaOH; therefore, mols NaOH/2 = mols H2SO4.
Then M H2SO4 = mols H2SO4/L H2SO4. You know mols and L, solve for M.
To determine the concentration of the sulfuric acid solution, you can use the equation:
M1V1 = M2V2
Where:
M1 = concentration of sulfuric acid solution
V1 = volume of sulfuric acid solution (in this case, 25.0 ml)
M2 = concentration of sodium hydroxide (NaOH) solution (0.20 M)
V2 = volume of sodium hydroxide solution (in this case, 20.00 ml)
Rearranging the equation, we have:
M1 = (M2 * V2) / V1
M1 = (0.20 M * 20.00 ml) / 25.0 ml
M1 = 0.16 M
Therefore, the concentration of the sulfuric acid solution is 0.16 M.