what is the radius and height of container that will contain 42 barrels of oil?
42barrels * 42gal/barrel = 1764 gal.
1764gal. * 1barrel/55gal. = 32 - 55 gal barrels.
V1 = pi*r^2 * h = 3.14*(11.65)^2 * 34.9 = 14,881 in^3. = Vol. of a 55 gal. container.
V2 = 32*V1 = 32 * 476,187 in^3 = Vol. of the 1764 gal container.
Let r2 = 1.5r1 = 1.5 * 11.65 = 17.5 in.
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V2 = pi*r2^2 * h = 476,187 in^3.
3.14*(17.5)^2 * h = 476,187. h = ?.
To determine the radius and height of a container that can hold 42 barrels of oil, we need to know the dimensions of a barrel.
A standard oil barrel, also known as a barrel of oil, has a capacity of 42 gallons. However, the dimensions can vary.
Assuming a cylindrical shape, the volume of each barrel can be calculated using the formula for the volume of a cylinder:
Volume = π * r^2 * h
Where:
- π is a mathematical constant, approximately equal to 3.14159.
- r is the radius of the base of the cylinder.
- h is the height of the cylinder.
Since the volume of one barrel is known (42 gallons), we can convert it to find the volume in cubic units.
1 US gallon is approximately equal to 0.1337 cubic feet. Therefore, 42 gallons is equal to 42 * 0.1337 cubic feet.
Let's assume the volume of one barrel is equal to V cubic feet.
Now, for 42 barrels, the total volume of the container would be 42 * V cubic feet.
Once you have the total volume, you can find the dimensions of the container by solving for the radius (r) and height (h) in the volume formula.
However, to proceed further and obtain specific values for the radius and height, you need to provide the dimensions of a single oil barrel, such as the height and diameter or radius.