One side of a square is 2x + 5 centimeters long. The area of the square is ax^2 + bx + c square centimeters. What is the value of a + b + c?

I litteraly dont undestand this problem at all please help me and guide me throught it.

Okay, well to find the area of a square you would need to do one side times another side which would result in the area. According to this equation in polynomials, it would be (2x+5) cm times (2x+5) cm....

Once you FOIL these sides together you should get something on the lines of:
"4x^2+20x+25"...
You need to add the a, b and c within the polynomial so we can take 4, 20 and 25 respectively which means 4 + 20 + 25 = 49...

ty for explaining it

Sure! Let's break down the problem step by step.

We're given that one side of a square is 2x + 5 centimeters long. To find the area of a square, we need to square the length of its side.

To find the area of this square, we can substitute (2x + 5) for the length of the side in the formula for the area of a square.

Area of a square = (side length)^2

So, the area of the square is (2x + 5)^2.

To determine the value of a + b + c, we need to expand and simplify (2x + 5)^2.

Expanding this expression, we have:

(2x + 5)^2 = (2x + 5)(2x + 5) = 4x^2 + 10x + 10x + 25 = 4x^2 + 20x + 25

Now, we can observe that the area of the square can be expressed as ax^2 + bx + c, which means:

a = 4
b = 20
c = 25

Finally, we can find the value of a + b + c:

a + b + c = 4 + 20 + 25 = 49

Therefore, the value of a + b + c is 49.

I hope this explanation helps! Let me know if you have any further questions.