How many volleyball games would Rana have to schedule if there were 10 teams in the league and each team played each other twice?
I've got a easier way solve this question: using the table of value.
When there is 1 teams, Rana can hold 0 game;
When there is 2 teams, Rana can hold 1 game;
When there is 3 teams, Rana can hold 3 games; (Suppose there are team A, B and C, A-B, A-C, B-C, three)
When there is 4 teams, Rana can hold 6 games; (Suppose there are team A, B, C, D. A-B, A-C, A-D, B-C, B-D, C-D)
When there is 5 teams, Rana can hold 10 games;
.......
When there is 10 teams, Rana can hold 45 games.
NOTE: The players need to play with each other twice, so there will be 45*2= 90 games.
where did you get that 10,2???? i don't get it
and how did you get 45???????????
Number of games in one round
= C(10,2) = 45
but they are playing two rounds, so
total number of games = 90
ur mom
To find the number of volleyball games Rana would have to schedule, we need to consider that each team plays every other team twice.
The number of total games played by one team against all other teams can be found using the combination formula "nC2," where "n" is the number of teams. In this case, we need to compute 10C2.
The combination formula for "nC2" is given by:
(n!)/((n-2)! * 2!)
Let's calculate it step-by-step:
1. Calculate 10 factorial (10!):
10! = 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 3,628,800
2. Calculate (10-2)!:
(10-2)! = 8! = 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 40,320
3. Calculate 2!:
2! = 2 × 1 = 2
4. Substitute the values into the combination formula:
10C2 = (10!) / ((10-2)! * 2!) = 3,628,800 / (40,320 * 2) = 3,628,800 / 80,640 = 45
Therefore, Rana would have to schedule 45 volleyball games if there are 10 teams in the league and each team played each other twice.