Three fourths of a number increased by 4 is at most 19
3/4 x + 4 <= 19
This was very helpful, thanks.
Let's solve this step-by-step:
Step 1: Let's assume the unknown number as "x".
Step 2: Three fourths of the number is (3/4) * x.
Step 3: Adding 4 to three fourths of the number gives us the expression (3/4) * x + 4.
Step 4: According to the given information, the expression (3/4) * x + 4 is at most 19.
Step 5: We can write the inequality as (3/4) * x + 4 ≤ 19.
Step 6: Now, let's solve the inequality for x:
Subtracting 4 from both sides: (3/4) * x ≤ 15.
Step 7: To get rid of the fraction, we'll multiply both sides of the inequality by 4:
(4) * (3/4) * x ≤ (4) * 15.
Simplifying, we have: 3x ≤ 60.
Step 8: Divide both sides of the inequality by 3:
x ≤ 20.
Therefore, the number x is at most 20.
To solve this problem, we can follow these steps:
Step 1: Let's assume the number we are trying to find is represented by "x".
Step 2: We know that three fourths of the number is (3/4) * x, and when this value is increased by 4, the expression becomes (3/4) * x + 4.
Step 3: According to the problem, this expression is at most 19. So we can write the inequality as (3/4) * x + 4 ≤ 19.
Step 4: Now, we can solve this inequality to find the maximum value of x.
Subtract 4 from both sides of the inequality:
(3/4) * x ≤ 15
Multiply both sides of the inequality by 4/3 to isolate x:
x ≤ 20
Step 5: Therefore, the number x is at most 20, which means any number less than or equal to 20 will satisfy the given condition.
Note: If the question asks for the number to be an integer, we can further refine the solution by stating that x is an integer less than or equal to 20.