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What is the smallest positive integer which, when divided by 6 gives remainder 1 and when divided by 11 gives remaider 6.
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How many integers bewteen 200 and 500 inclusive leave a remainder 1 when divided by 7 and a remainder 3 when divided by 4?
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To find the number of integers between 200 and 500 (inclusive) that satisfy the given conditions, we
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How many integers between 200 and 500 inclusive leave a remainder 1 when divided by 7 and a remainder 3 when divided by 4?
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446 divided by 11
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What is the smallest possible positive integer x>5 , that leaves a remainder of 5 whenever it is divided by 14 , 8 or 77 ?
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14 = 2x7 8 = 2x2x2 77 = 7x11 LCM = 7x11x8 = 616 adding 5+616 = 621 check: 621รท8 leaves remainder of
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Find the least positive integer that leaves the remainder 3 when divided by 7, remainder 4 when divided by 9, and remainder 8
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See solution to the same problem at: http://www.jiskha.com/display.cgi?id=1343870416
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what is the least common positive integer that meets the following conditions:
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You can use the Chinese Remainder Theorem. Notation: If a number X divided by N has a remainder of
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what is the least common positive integer that meets the following conditions:
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divisible by 9 R 6 15 24 33 42 51 60 69 78 87 96 8 remainder 5 13 21 29 37 44 52 60 7 remainder 4 11
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Find a positive integer smaller than 500 that has a remainder of 3 when divided by 5, a remainder of 6 when divided by 9, and a
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The answer must appear on all these lists: 498, 493, 488, 483,... 13, 8, 3. 492, 483, 474, 465,...
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