How much energy in joules does it take to raise the temperature of 255 g of water by 12.5 C ?
To calculate the amount of energy required to raise the temperature of a substance, we can use the formula:
Q = m * c * ΔT
Where:
Q = energy transferred (in joules)
m = mass of the substance (in grams)
c = specific heat capacity of the substance (in joules/gram Celsius)
ΔT = change in temperature (in Celsius)
Given:
m = 255 g
c = 4.184 J/g°C (specific heat capacity of water)
ΔT = 12.5°C
Substituting the given values into the equation:
Q = (255 g) * (4.184 J/g°C) * (12.5°C)
Q ≈ 13,169.175 joules
Therefore, it would take approximately 13,169.175 joules of energy to raise the temperature of 255 grams of water by 12.5°C.
To calculate the amount of energy required to raise the temperature of a substance, you can use the formula:
Q = m * c * ΔT
Where:
Q is the energy (in joules),
m is the mass of the substance (in grams),
c is the specific heat capacity of the substance (in joules per gram per degree Celsius), and
ΔT is the change in temperature (in degree Celsius).
In this case:
m = 255 g (mass of water)
c = 4.18 J/g°C (specific heat capacity of water)
ΔT = 12.5°C (change in temperature)
Substituting the values into the formula, we have:
Q = 255 g * 4.18 J/g°C * 12.5 °C
Calculating this expression will give you the value of energy in joules. So, let's proceed with the calculation:
Q = 134060.625 J
Therefore, it takes approximately 134,060.625 joules of energy to raise the temperature of 255 grams of water by 12.5 degrees Celsius.