How much Cerium sulfate is needed to make a saturated solution in 100mL of water at 30 degrees Celsius?
How much Cerium sulfate is needed to make a saturated solution in 100mL of water at 30 degrees Celsius?
To calculate the amount of Cerium sulfate needed to make a saturated solution in 100 mL of water at 30 degrees Celsius, we need to know the solubility of Cerium sulfate at that temperature. The solubility of a substance indicates how much of it can dissolve in a given amount of solvent.
To find the solubility of Cerium sulfate at 30 degrees Celsius, you can consult a solubility table or search for it in an appropriate reference material. Once you have the solubility value, you can calculate the amount of Cerium sulfate needed.
Let's assume, for example, that the solubility of Cerium sulfate at 30 degrees Celsius is 50 grams per 100 mL of water. To make a saturated solution, you would need to add this amount of Cerium sulfate to the 100 mL of water.
Therefore, to make a saturated solution of Cerium sulfate in 100 mL of water at 30 degrees Celsius, you would need 50 grams of Cerium sulfate.
https://en.wikipedia.org/wiki/Solubility_table
read the table: 7.35 grams as I recall, I assume you mean Cerium(III)Sulfate di hydrate
Answer: 18g
@50 degrees Celsius 80g/100cm^3
@40 degrees Celsius 62g/100cm^3
80-62=18g
Answer 18g