Decide what values of the variable cannot possibly be solutions for each equation. Do not solve.
2/x+3 - 5/x-1= -5/x^2+2x-3
Did you even look at the solution I gave you here
http://www.jiskha.com/display.cgi?id=1478637677
This is the same type of problem.
btw, the denominator on the right side factors to
(x+3)(x-1)
I did
so does x not equal -3,1,-3, and 1
You are correct, but why list the values twice?
To determine the values of the variable that cannot be solutions for the equation, we need to identify any potential restrictions on the variable that would make the equation undefined or lead to division by zero.
Let's consider each part of the equation individually:
1. The expression "2/x+3"
In this expression, the variable is in the denominator. To avoid division by zero, x cannot be equal to 0.
2. The expression "5/x-1"
Similarly, in this expression, the variable is in the denominator. To avoid division by zero, x cannot be equal to 1.
3. The expression "-5/x^2+2x-3"
Here, the variable x is squared. To avoid division by zero, x^2 cannot be equal to 0. Therefore, x cannot be equal to 0.
Considering the restrictions we identified, the values of the variable that cannot possibly be solutions for the equation are x = 0 and x = 1.
Note: It's important to keep in mind these restrictions when solving the equation to ensure we don't include values that would make the equation undefined or result in division by zero errors.