A gymnast is performing a floor routine. In a tumbling run she spins through the air, increasing her angular velocity from 3.00 to 5.75 rev/s while rotating through one-half of a revolution. How much time does this maneuver take?
Divide 0.5 revolutions by the average angular velocity (4.38 rev/s). The answer will be in seconds.
Thanks. Is it possible for you to check the three questions i've posted earlier? I am having a problem with them. Thanks again!
Can you please explain how you got 4.38rev/s?
avg= (final+initial)/2= (3+ 5.75)/2=4.38
Thanks!
this is not right.
To calculate the average angular velocity, you need to find the average of the initial and final angular velocities. In this case, the initial angular velocity is 3.00 rev/s and the final angular velocity is 5.75 rev/s.
To find the average, you can simply add the initial and final angular velocities together and divide by 2:
Average angular velocity = (3.00 rev/s + 5.75 rev/s) / 2
= 8.75 rev/s / 2
= 4.38 rev/s
Therefore, the average angular velocity of the gymnast during this feat is 4.38 rev/s.
To calculate the average angular velocity, you need to find the average of the initial and final angular velocities.
In this case, the initial angular velocity is given as 3.00 rev/s and the final angular velocity is given as 5.75 rev/s.
To find the average, you add the initial and final angular velocities together and then divide by 2.
So, (3.00 + 5.75) / 2 = 8.75 / 2 = 4.38 rev/s.
Therefore, the average angular velocity for the gymnast's maneuver is 4.38 rev/s.
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