What mass of hydrogen gas is produced when 3.0 mol of iron react with excess hydrochloric acid according to the reaction below
2Fe + 6HCl --> 2FeCl3 + 3H2
We compare the moles of H2 with Fe if 2 moles of Fe gives 3 moles of H2 so 3 moles of Fe would give 4.5 moles of H2. Now by Formula
N of moles=Mass/molar mass
molar mass of H2 is 2 and moles is 4.5
we multiply these values to get mass
2*4.5=9
9g of H2 is produced :)
To calculate the mass of hydrogen gas produced, we need to find the stoichiometric ratio between iron (Fe) and hydrogen gas (H2) in the equation.
The balanced equation shows that for every 2 moles of iron (Fe) that react, 3 moles of hydrogen gas (H2) are produced. This means there is a 2:3 ratio between iron and hydrogen gas in the reaction.
Since we are given 3.0 moles of iron (Fe), we can use this ratio to determine the number of moles of hydrogen gas produced.
First, we convert moles of iron (Fe) to moles of hydrogen gas (H2) using the stoichiometric ratio:
3.0 mol Fe × (3 mol H2 / 2 mol Fe) = 4.5 mol H2
Now, to determine the mass of hydrogen gas, we need to use the molar mass of hydrogen gas, which is 2.02 g/mol.
Mass of hydrogen gas (H2) = 4.5 mol H2 × 2.02 g/mol H2 = 9.09 g
Therefore, the mass of hydrogen gas produced when 3.0 mol of iron reacts with excess hydrochloric acid is 9.09 grams.