The atomic mass of an element is 27.and its equivalent mass is 9.the vapour density of chloride is
To find the vapor density of a chloride compound, we need to know the atomic mass of the element and the equivalent mass of the compound.
Given that the atomic mass of the element is 27 and the equivalent mass of the compound is 9, we can determine the vapor density using the following steps:
Step 1: Determine the molar mass of the chloride compound.
The molar mass of a compound is the sum of the atomic masses of all its constituent atoms. Since the atomic mass of the element (27) is equal to three times the equivalent mass of the compound (9), we can deduce that the compound contains three atoms of the element.
Molar mass of the chloride compound = (27 g/mol) × 3 = 81 g/mol
Step 2: Find the molecular mass of the chloride compound.
The molecular mass refers to the mass of one molecule of the compound. It can be obtained by dividing the molar mass by Avogadro's number (6.022 × 10^23 mol⁻¹).
Molecular mass of the chloride compound = (81 g/mol) / (6.022 × 10^23 mol⁻¹)
Step 3: Calculate the vapor density.
Vapor density is the ratio of the mass of a given volume of a gas to the mass of an equal volume of a standard gas, typically hydrogen or air. To calculate vapor density, we divide the molecular mass of the compound by the molecular mass of the standard gas.
Vapor density = (Molecular mass of the chloride compound) / (Molecular mass of the standard gas)
The molecular mass of hydrogen is approximately 2 g/mol. Considering hydrogen as the standard gas, we can calculate the vapor density as:
Vapor density = (81 g/mol) / (2 g/mol) = 40.5
Therefore, the vapor density of the chloride compound is approximately 40.5.