A ball A having a speed of 44.0 ms-1
collides with another ball, B, of the same mass
which is initially at rest. After the collision A is deflected, 45.0 from its initial direction and
B moves off at an angle of 30.0° to the original direction of A.
a. What is the nature of the collision? (1 Mark)
b. What is the speed of each ball after the collision?
M*V1 + M*V2 = M*V3[45o] + M*V4[30o].
V1 + 0 = V3[45o] + V4[30o].
44 = V3*Cos45 + V4*Cos30.
Eq1: 0.707V3 + 0.866V4 = 44,
V3 = 62.2-1.22V4.
V3*sin45 + V4*sin30 = 0.
Eq2: 0.707V3 + 0.5V4 = 0,
1.414V3 + V4 = 0,
V4 = -1.414V3.
V3 = 62.2 - 1.22*(-1.414V3),
V3 = 62.2 + 1.73V3, V3 = -85.2 m/s. = Velocity of ball A.
V4 = -1.414V3 = -1.414*(-85.2) = 120.5 m/s.= Speed of B.