An object of mass 1.00kg is moving over a horizontal circular path of radius 2.00m, with a speed of 3.00ms^-1. Determine:

(a) its centripetal acceleration

(b) its kinetic energy

(c) its period

(d) its angular velocity

(a) Av = v^2/r = 9/2

(b) (1/2) m v^2

(c) distance = 2 pi r
time = distance / v

(d) omega = v/r

Hey, this is all in your text easy.

What do you mean? Please help, i'm still confused

google centripetal acceleration

for example

http://formulas.tutorvista.com/physics/centripetal-acceleration-formula.html

Please, these problems are just plug in the formula problems, no thought required. Please look them up in your text or Google.

To determine the values, we can use the following formulas:

(a) Centripetal acceleration (a):
Centripetal acceleration is given by the formula:

a = v^2 / r

Where:
a = Centripetal acceleration
v = Velocity of the object
r = Radius of the circular path

Substituting the given values:

v = 3.00 m/s
r = 2.00 m

a = (3.00 m/s)^2 / 2.00 m
a = 9.00 m^2/s^2 / 2.00 m
a = 4.50 m/s^2

Therefore, the centripetal acceleration of the object is 4.50 m/s^2.

(b) Kinetic energy (K):

Kinetic energy is given by the formula:

K = 0.5 * m * v^2

Where:
K = Kinetic energy
m = Mass of the object
v = Velocity of the object

Substituting the given values:

m = 1.00 kg
v = 3.00 m/s

K = 0.5 * 1.00 kg * (3.00 m/s)^2
K = 0.5 kg * 9.00 m^2/s^2
K = 4.50 kg m^2/s^2

Therefore, the kinetic energy of the object is 4.50 kg m^2/s^2.

(c) Period (T):

The period of an object moving in a circular path is the time taken by it to complete one full revolution. The formula for the period is:

T = 2πr / v

Where:
T = Period
r = Radius of the circular path
v = Velocity of the object

Substituting the given values:

r = 2.00 m
v = 3.00 m/s

T = 2π * 2.00 m / 3.00 m/s
T = 4π/3 seconds

Therefore, the period of the object is 4π/3 seconds.

(d) Angular velocity (ω):

The angular velocity of an object moving in a circular path is the rate at which it rotates around the center. The formula for angular velocity is:

ω = v / r

Where:
ω = Angular velocity
v = Velocity of the object
r = Radius of the circular path

Substituting the given values:

v = 3.00 m/s
r = 2.00 m

ω = 3.00 m/s / 2.00 m
ω = 1.50 rad/s

Therefore, the angular velocity of the object is 1.50 rad/s.