A rectangular fish tank has a base area of 0.3 m squared and height 30 cm and is filled with 80 L of water. Ten large fish with volume 50 cm cubed each are placed into the tank. By how much does the water rise?
each 1cm layer of water has a volume of 30^2 * 1 = 900 cm^3
So, what's the total volume of the fish? Divide that by 900cm^3 to find how much the water level rises.
To determine how much the water level rises, we need to calculate the total volume of the ten large fish and compare it to the volume of water in the tank.
Step 1: Convert the base area from m² to cm².
Since 1 m = 100 cm, the base area in cm² = 0.3 m² x (100 cm/1 m)² = 30,000 cm².
Step 2: Convert the height from cm to m.
Since 1 m = 100 cm, the height in m = 30 cm/100 = 0.3 m.
Step 3: Calculate the volume of the tank.
Volume of the tank = base area x height = 30,000 cm² x 0.3 m = 9,000 cm³.
Step 4: Convert the volume of water from liters to cm³.
Since 1 L = 1,000 cm³, the volume of water in cm³ = 80,000 cm³.
Step 5: Calculate the total volume of the ten large fish.
Volume of one fish = 50 cm³.
Total volume of ten fish = 10 fish x 50 cm³ = 500 cm³.
Step 6: Calculate the rise in water level.
Rise in water level = Total volume of fish / Base area
= 500 cm³ / 30,000 cm²
= 0.0167 cm.
Therefore, the water level in the fish tank will rise by approximately 0.0167 cm when ten large fish with a volume of 50 cm³ each are placed in the tank.