A sample of ice at 0-degree melts after absorbing kJ of heat. How many kg of H20 are contained in the sample?
To determine the number of kilograms of H2O contained in the sample, we need to use the concept of specific heat and the amount of heat absorbed.
The specific heat capacity of ice is 2.09 J/g·°C. We need to convert the given heat value from kJ to J by multiplying it by 1000, as 1 kJ = 1000 J.
Let's assume the mass of the ice sample is m grams. We know that the temperature change is from 0°C (the melting point of ice) to the melting point of ice, which is also 0°C. Therefore, the temperature change is 0°C - 0°C = 0°C.
The amount of heat absorbed can be calculated using the formula:
Q = m * c * ΔT
Where:
Q = heat absorbed (in joules)
m = mass of the substance (in grams)
c = specific heat capacity (in J/g·°C)
ΔT = change in temperature (in °C)
In this case, the equation becomes:
Q = m * 2.09 J/g·°C * 0°C
Q = 0 J
Since the amount of heat absorbed is 0 J, this means the ice did not melt. Therefore, there are no kilograms of H2O contained in the sample.
Please verify the heat value provided, as it appears to be inconsistent with the given conditions.