(2-sin^2x)/-sinx=sinx

Is this doable. That's the answer but I can't get the l.s to equal r.s

"I can't get the l.s to equal r.s"

If you are trying to show that it is an identity, good luck , since it is not (try it with 30° for x)

So I will assume you are solving:
(2-sin^2x)/-sinx=sinx
2 - sin^2 x = -sin^2 x
2 = 0 , which is a contradiction,

there is no solution, nor is it an identity.