N2(g) + 3H2(g) -> 2NH3(g)
How many grams of ammonia are formed from 14.0 grams of nitrogen?

14/2 = 7 grams of ammonia

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  1. The equation is balanced, For each mole of N2 (nitrogen), twice that number of moles of ammonia is formed.

    moles nitrogen= 14/28=.5 moles
    moles ammonia= 2*.5=1
    grams ammonia= (14+3)*1 = 17 grams.

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