N2(g) + 3H2(g) -> 2NH3(g)

How many grams of ammonia are formed from 14.0 grams of nitrogen?

14/2 = 7 grams of ammonia

The equation is balanced, For each mole of N2 (nitrogen), twice that number of moles of ammonia is formed.

moles nitrogen= 14/28=.5 moles
moles ammonia= 2*.5=1
grams ammonia= (14+3)*1 = 17 grams.

Well, if you take 14.0 grams of nitrogen and follow the balanced equation, you'll get a 2:1 ratio. So, for every 2 moles of ammonia, you'll need 1 mole of nitrogen. Since the molar mass of nitrogen is 14 grams/mol and the molar mass of ammonia is 17 grams/mol, we can calculate the answer.

14 grams of nitrogen * (2 moles of ammonia / 2 moles of nitrogen) * (17 grams of ammonia / 1 mole of ammonia) = 14 grams of ammonia!

So, 14.0 grams of nitrogen will give you 14.0 grams of ammonia. Now that's some efficient nitrogen-to-ammonia conversion!

To determine the amount of ammonia formed, we need to use the balanced chemical equation and the molar mass of nitrogen (N2) and ammonia (NH3).

From the balanced equation:

N2(g) + 3H2(g) -> 2NH3(g)

We can see that 1 mole of nitrogen (N2) reacts to form 2 moles of ammonia (NH3).

The molar mass of nitrogen (N2) is 28.0 g/mol and the molar mass of ammonia (NH3) is 17.0 g/mol.

So, we can use the following steps to solve the problem:

1. Convert the given mass of nitrogen to moles:

Given mass = 14.0 g
Molar mass of nitrogen = 28.0 g/mol

Moles of N2 = given mass / molar mass
= 14.0 g / 28.0 g/mol
= 0.5 mol

2. Use the mole ratio from the balanced equation to determine the moles of ammonia formed:

Moles of NH3 = moles of N2 * (2 moles of NH3 / 1 mole of N2)
= 0.5 mol * (2 mol NH3 / 1 mol N2)
= 1 mol

3. Convert the moles of ammonia to grams:

Molar mass of ammonia = 17.0 g/mol

Mass of NH3 = moles of NH3 * molar mass
= 1 mol * 17.0 g/mol
= 17.0 g

Therefore, 14.0 grams of nitrogen will form 17.0 grams of ammonia.

To determine the number of grams of ammonia formed from 14.0 grams of nitrogen, you need to use the balanced chemical equation and the concept of stoichiometry.

The balanced chemical equation is:
N2(g) + 3H2(g) -> 2NH3(g)

From the equation, you can see that 1 mole of nitrogen (N2) reacts to form 2 moles of ammonia (NH3).

First, you need to convert the given mass of nitrogen (14.0 grams) into moles. To do this, divide the mass by the molar mass of nitrogen, which is approximately 28.0 grams/mole (since N2 has a molar mass of 28.0 g/mol).

14.0 grams N2 × (1 mole/ 28.0 grams) = 0.5 moles of N2

Now that you have the moles of nitrogen, you can use the stoichiometric ratio from the balanced equation to find the moles of ammonia produced.

According to the balanced equation, 1 mole of nitrogen (N2) reacts to form 2 moles of ammonia (NH3). Therefore, for every 1 mole of N2, you get 2 moles of NH3.

0.5 moles of N2 × (2 moles NH3/ 1 mole N2) = 1 mole of NH3

Finally, you can convert the moles of ammonia into grams by multiplying by the molar mass of ammonia, which is approximately 17.0 grams/mole (since NH3 has a molar mass of 17.0 g/mol).

1 mole NH3 × (17.0 grams/ 1 mole) = 17.0 grams of NH3

So, from 14.0 grams of nitrogen, you would form approximately 17.0 grams of ammonia.