The radius of a neon atom is 3.1×10(exponent -11) meters. The radius of a silver atom is 1.65×10(exponent -10) meters. What is the diffrence in the raddi of the two atoms?
A.0.000000000134m
B.0.0000000005115m
C.0.000000000196m
D.0.0134m
To find the difference in the radii of the two atoms, you need to subtract the radius of the neon atom from the radius of the silver atom.
Radius of a neon atom = 3.1×10^(-11) meters
Radius of a silver atom = 1.65×10^(-10) meters
Difference in radii = Radius of silver atom - Radius of neon atom
Difference in radii = 1.65×10^(-10) - 3.1×10^(-11)
To simplify the calculation, you can express both radii with the same exponent of 10. Let's express both radii with an exponent of 10^(-10).
1.65×10^(-10) = 1.65×10^(-10) × 1×10^(0) = 1.65×10^(-10 + 0) = 1.65×10^(-10)
3.1×10^(-11) = 3.1×10^(-11) × 1×10^(0) = 3.1×10^(-11 + 0) = 3.1×10^(-11)
Now, you can subtract the two radii:
Difference in radii = 1.65×10^(-10) - 3.1×10^(-11) = 1.65×10^(-10) - 0.31×10^(-10) = 1.34×10^(-10)
So, the difference in the radii of the two atoms is 1.34×10^(-10) meters.
Option A. 0.000000000134m is the correct answer.