What amount of naoh require to neutralize 1kg HCl
To determine the amount of NaOH required to neutralize 1 kg of HCl, we need to use the concept of mole-to-mole ratios.
1. Write the balanced chemical equation for the neutralization reaction between NaOH and HCl:
NaOH + HCl -> NaCl + H2O
2. Determine the molar mass of HCl and NaOH. The molar mass of HCl is approximately 36.5 g/mol, and the molar mass of NaOH is approximately 40 g/mol.
3. Convert the mass of HCl from kilograms to grams:
1 kg = 1000 grams
4. Calculate the number of moles of HCl:
moles of HCl = mass of HCl / molar mass of HCl
moles of HCl = 1000 g / 36.5 g/mol
moles of HCl ≈ 27.4 mol
5. Based on the balanced chemical equation, we know that the mole ratio between NaOH and HCl is 1:1.
6. The amount of NaOH required can be calculated using the following formula:
moles of NaOH = moles of HCl
moles of NaOH ≈ 27.4 mol
7. Finally, calculate the mass of NaOH required:
mass of NaOH = moles of NaOH * molar mass of NaOH
mass of NaOH ≈ 27.4 mol * 40 g/mol
mass of NaOH ≈ 1096 g
Therefore, approximately 1096 grams (or 1.096 kilograms) of NaOH is required to neutralize 1 kilogram of HCl.