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Calc

A baseball is thrown upwards from a height of 2 meters with an initial velocity of 10 meters per second. Use the fact that -9.8 meters per second squared is constant acceleration due to gravity to answer the following:

The maximum height of the ball

The time it takes for the ball to hi the ground.

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  1. height = -4.9t^2 + 10t + 2
    d(height)/dt = -9.8t + 10
    = 0 at max height

    9.8t = 10
    t = 10/9.8

    height = -4.9(10/9.8)^2 + 10(10/9.8) + 2 = appr 7.102 m is the max height

    when it reaches the ground
    0 = -4.9t^2 + 10t + 2
    4.9t^2 - 10t- 2 = 0
    t = (10 ± √139.2)/9.8 = 1.306 seconds or a negative

    check my arithmetic

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